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Since
the majority of failures in boating have to do with
something electrical, we thought it might be a good idea
to post a series of articles on electricity and trouble
shooting. Electricity 101 will be the first in that
series.
Understanding
the terminology of electricity is the first step to
starting to understand electrical theory. I personally
like to compare electricity to the more straight forward
discipline of simple plumbing. I am assuming that each
of you has, at some time, used a water hose. That is the
simple plumbing to which I am referring.
When
you turn on the spigot connected to a water hose, the
amount of pressure that you have at the end of the hose
depends on how much you open the spigot. This pressure
can be measured in pounds per square inch. With the
spigot opened fully you will have a constant pressure at
the end of the hose. The pressure can vary if you reduce
the length or diameter of the hose or add a nozzle which
restricts flow at the end therefore increasing pressure.
Electricity
works the same way. Think of voltage
as equivalent to pressure
in the water hose and the hose itself as the wire that
carries the electricity. Water flowing through the hose
has resistance
from the inside hose surface itself as well as at the
nozzle. This same resistance occurs as current flows
through an electric wire. However, in electricity the
resistance is measure by a unit called the
Ohm. With greater pressure,
water flow increases through the nozzle and resistance
is greater. The same is true with electricity, with
greater voltage (pressure) the flow of electrical
current increases though the wire and resistance (Ohms)
also increase. On the other hand, if pressure drops,
water flow decreases. The same happens if voltage drops,
current slows down causing a "brownout".
Resistance
is an important part of the electrical equation. A
smaller hole in the nozzle of a water hose increases
resistance. In pipes, friction on the walls makes
resistance. In wires there is resistance from the wire
itself and, if you add a light bulb with a fine tungsten
filament, even more resistance is produced. You might
think of the light bulb as the nozzle. The larger the
pipe the less resistance is created, the same holds with
wire; the larger the wire, the less the resistance.
Water
flow is measured in gallons per minute. Electrical
current flow is measured by the Ampere or Amp.
So
far we have explored in the plumbing analogy the
following:
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Plumbing
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Electricity
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Pressure
=
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Voltage
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Resistance
=
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Ohm
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Water
flow rate =
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Ampere
(Current)
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How
do these all interact? This brings in something called
Ohm's Law. Let's say you have turned the spigot on only
half way, producing some resistance, with a hose
attached to fill a pot with water. As you fill the pot
with a constant pressure from the spigot you have
constant flow rate through the hose. The same is true
with electricity; with a constant voltage you have a
constant flow of Amps through the wire. If you open the
spigot all the way and double the pressure you are also
doubling the flow rate. Electricity works the same way,
if we double the voltage we double the current in Amps.
Remember
the resistance part? Water resistance flowing through a
hose is the same as resistance through a wire. This
resistance is measured in Ohms. The amount of this
resistance can be measured by pressure and flow rate or
voltage and amps. One Ohm of resistance lets one Amp of
current flow when the pressure is one volt. Two volts
would give you two amps of current, Six volts would give
you 6 amps, etc. You can calculate the amount of Ohms,
Volts or Amps with the following equation.
PRESSURE(VOLTS)/FLOW(AMPS)
= RESISTANCE (Ohm)
From
this equation we can calculate any of the three
variables if we know any two. For example, if we applied
12 volts and were able to measure that the 12 volts was
producing 2 amps, what is our resistance in Ohms?
12
Volts/2 Amps = 6 Ohms
What's
a Watt?
Back
to our plumbing analogy...the amount of power of the
water flow can be controlled. Obviously, the power of a
stream of water can be increase by adding a nozzle.
(Ever try to wash leaves off the driveway without a
nozzle or putting your thumb over the end of the hose?)
Power comes from the volume and speed of the water jet.
This is similar to power (Watts) of electricity. Volts
times Amps give Watts.
As
an example of why this is important, try to follow the
following example. Remember
Volts X Amps = Watts
Each
of the lights below are 12 watts. As such they should
give about the same amount of light. What we want to
know is how many Amps are used under various voltage
situations. To measure Amps we will use the formula but
the illustration will show an Ampere Meter.
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6 Volts
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6 Volts X 2 Amps = 12 Watts
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12 Watts
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12
Volts
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12 Volts X 1 Amp = 12 Watts
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12 Watts
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120
Volts
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120 X .1 = 12 Watts
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If
you study the figure above more carefully you will
notice that to produce the same amount of light at lower
voltages more current (Amps) must flow to the bulbs
tungsten element. In order to have more current flow
through the 12 Volt or 6 Volt filament, the filament in
the 12 Volt bulb must have a lower resistance than the
filament in the 120 Volt light. Consequently the
filament in the 6 Volt bulb must have a lower resistance
than the 12 Volt bulb so that double the current will
flow through its filament even though only half the
pressure or voltage is there to make the current.
Remember
that resistance, in OhmS, is also easy to calculate. It
is the ratio of voltage to current:
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Resistance
(Ohm) =
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Volt |
| Amp |
Why
are we concerned with the current flow rate or Amperes?
Well...when connected to shore power or using a
generator to generate 120 volts we might not be too
concerned. However, when we are at anchor and operating
off our batteries, we only have so many Amps we can use
before your batteries die.
Using
these formulas let's try an example as shown below.
The
diagram represents a 12 Volt battery powering a light
bulb. We are measuring voltage with a volt meter,
amperes with an amp meter and Ohms with an Ohm meter.
(Actually, you can purchase a multimeter which has the
ability to measure all of these) As shown, we have 12
Volts, 3 Amps and 4 Ohms. By using the formulas below we
can find each of these measurements by only knowing two.

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12
Volt
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=
3 Ampere (Amps) |
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4
Ohm
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4
Ohm X 3 Ampere
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=
12 Volt |
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12
Volt
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=
4 Ohm |
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3
Amps
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As
the current flows through the resistor (light bulb) the
resistor gets hot. How hot you ask, how about hot enough
to generate 36 Watts, the heat of a small light bulb.
12
Volt X 3 Amps = 36 Watt
Now
that you know the basics hopefully future articles will
make more sense. We will, in the future, be covering a
few more advanced items and then a series of articles on
troubleshooting and solving electrical mysteries.
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